Answer :
Answer:
[tex]J" = (-5,3)[/tex]
Step-by-step explanation:
Given
[tex]J = (5,-3)[/tex]
Reflections: over y and x axis to create J"
Required
Determine J"
When reflected over y axis:
[tex]J'(x,y) = J(-x,y)[/tex]
We have that:
[tex]J = (5,-3)[/tex]
So:
[tex]J(-x,y) = (-5,-3)[/tex]
Hence
[tex]J' = (-5,-3)[/tex]
When reflected over x axis:
[tex]J"(x,y) = J'(x,-y)[/tex]
We have that:
[tex]J' = (-5,-3)[/tex]
So:
[tex]J(x,-y) = (-5,3)[/tex]
Hence
[tex]J" = (-5,3)[/tex]
Answer:
(5,3)
Step-by-step explanation:
I put it in and it came out right so