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A quarter rolls off a table with an initial horizontal velocity of 0.24 m/s. If the quarter lands 0.42 seconds later on the ground. How far from the table did it land?

Answer :

MathPhys

Answer:

0.10 m

Explanation:

Given in the x direction:

v₀ = 0.24 m/s

a = 0 m/s²

t = 0.42 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (0.24 m/s) (0.42 s) + ½ (0 m/s²) (0.42 s)²

Δx ≈ 0.10 m

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