Ye is riding home from a friend's house. After 5 minutes he is 4 miles from home, after 15 minutes Ye is 2 miles from home. Which equation models his distance from home y, in terms of minutes, x?

Answer :

MrRoyal

Answer:

[tex]y = -\frac{1}{5}x + 5[/tex]

Step-by-step explanation:

Given

[tex]5\ minutes = 4\ miles[/tex]

[tex]15\ minutes = 2\ miles[/tex]

Required

Determine the equation

y represents distance

x represents time

So, the given parameters can be modeled (x,y) as:

[tex](x_1,y_1) = (5,4)[/tex]

[tex](x_2,y_2) = (15,2)[/tex]

First, we need to determine the slope of the function.

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]m = \frac{2 - 4}{15 - 5}[/tex]

[tex]m = \frac{-2}{10}[/tex]

[tex]m = -\frac{1}{5}[/tex]

The equation can be determined using:

[tex]y - y_1 = m(x - x_1)[/tex]

Where

[tex]m = -\frac{1}{5}[/tex]

[tex](x_1,y_1) = (5,4)[/tex]

[tex]y - y_1 = m(x - x_1)[/tex]

becomes

[tex]y - 4 = \frac{-1}{5}(x - 5)[/tex]

Open bracket

[tex]y - 4 = -\frac{1}{5}x + 1[/tex]

Solve for y

[tex]y = -\frac{1}{5}x + 1 + 4[/tex]

[tex]y = -\frac{1}{5}x + 5[/tex]

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