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Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ, choose two or more points on the line and find the images of the points.)

Enter the slope-intercept equation for the image of line ℓ after a clockwise rotation of 90°. (Hint: To find the image of line ℓ, choose two or more points on t class=

Answer :

Answer:

[tex]y=\frac{1}{7}x-\frac{6}{7}[/tex]

Step-by-step explanation:

Two points (1, -1) and (0, 6) are lying on the given line.

Rule to find the coordinates of a point by the rotation of 90° clockwise is,

(x, y) → (y, -x)

Therefore, image points of (1, -1) and (0, 6) will be,

(1, -1) → (-1, -1)

(0, 6) → (6, 0)

Slope of the line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through (-1, -1) and (6, 0) will be,

m = [tex]\frac{0+1}{6+1}[/tex] = [tex]\frac{1}{7}[/tex]

Equation of the line passing through (6, 0) and slope = [tex]\frac{1}{7}[/tex]

y - y' = m(x - x')

y - 0 = [tex]\frac{1}{7}(x - 6)[/tex]

[tex]y=\frac{1}{7}x-\frac{6}{7}[/tex]

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