The line with the slope of 3/5 and goes through the point (1,2) is y = 3/5x + 7/5
The equation of a straight line is given by:
y = mx + b
where y, x are variables, m is the slope of the line and b is the y intercept.
Given the line has a slope of 3/5 and goes through the point (1,2). The equation of the line is given by:
[tex]y-y_1=m(x-x_1)\\\\y-2=\frac{3}{5}(x-1)\\\\y-2=\frac{3}{5}x-\frac{3}{5} \\\\y=\frac{3}{5}x+\frac{7}{5}[/tex]
