The price of a car decreases by 35% to £13000.
What was the car worth before the decrease?
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Answer:
€20,000
Step-by-step explanation:
% decrease = (original price of the car - new price) ÷ original price × 100
Let "x' represents the original price before the decrease.
New price = €13,000
% decrease = 35%
Plug in the values into the equation
[tex] 35 = \frac{x - 13,000}{x}*100 [/tex]
[tex] 35 = \frac{100x - 1,300,000}{x} [/tex]
Multiply both sides by x
[tex] 35*x = \frac{100x - 1,300,000}{x}*x [/tex]
[tex] 35x = 100x - 1,300,000 [/tex]
Subtract 100x from both sides
[tex] 35x - 100x = 100x - 1,300,000 - 100x [/tex]
[tex] -65x = -1,300,000 [/tex]
Divide both sides by -65
[tex] \frac{-65x}{65} = \frac{-1,300,000}{65} [/tex]
[tex] x = 20,000 [/tex]
The car was worth €20,000 before the decrease.