Answer :
Answer:
[tex]Probability = \frac{1}{24}[/tex]
Step-by-step explanation:
Given
[tex]Oranges = 3[/tex]
[tex]Apples = 5[/tex]
[tex]Banana = 2[/tex]
[tex]Total = 10[/tex]
Required
Determine the probability of 1 orange, 1 apple and 1 banana
Since, order is not important:
[tex]Probability = P(Orange) * P(Apple) * P(Banana)[/tex]
[tex]Probability = \frac{3}{10} * \frac{5}{9} * \frac{2}{8}[/tex]
The difference in the numerator is as a result of picking the fruit without replacement
[tex]Probability = \frac{30}{720}[/tex]
[tex]Probability = \frac{1}{24}[/tex]
Probability is simply how likely something is to happen.
The probability of 1 orange, 1 apple, and 1 banana are [tex]\frac{1}{24}[/tex]
On lunch counter,
Number of oranges = 3
Number of apples = 5
Number of bananas = 2
If 3 piece of fruit is selected then, probability of 1 orange, 1 apple and 1 banana
[tex]=\frac{3}{10}*\frac{5}{9} *\frac{2}{8} \\\\=\frac{30}{720}\\\\=\frac{1}{24}[/tex]
Therefore, the probability of selecting 1 orange, 1 apple, and 1 banana are [tex]\frac{1}{24}[/tex]
Learn more:
https://brainly.com/question/15589719