Answer :
Answer:
C₅H₁₀SO₂
Explanation:
From the given information:
The objective is to identify the empirical formula of the compound.
To start with determining the mass of carbon from carbon dioxide; we have:
[tex]Mass \ of \ Carbon = \dfrac{molar \ mass \ of \ C }{molar \ mass \ of \ CO_2}\times mass \ of \ CO_2[/tex]
Mass of carbon = 12/44 × 57.271 mg
Mass of carbon = 0.2727 × 57.271 mg
Mass of carbon = 15.6178 mg
The mass of hydrogen is:
[tex]Mass \ of \ Hydrogen= \dfrac{molar \ mass \ of \ H }{molar \ mass \ of \ H_2O}\times mass \ of \ H_2O[/tex]
[tex]Mass \ of \ Hydrogen= \dfrac{2\times 1.008 }{18}\times 23.444 \ mg[/tex]
Mass of hydrogen = 2.6257 mg
The mass of sulphur is:
[tex]Mass \ of \ Sulphur = \dfrac{molar \ mass \ of \ S }{molar \ mass \ of \ SO_2}\times mass \ of \ SO_2[/tex]
Mass of Sulphur = [tex]\dfrac{32.07}{64.06} \times \dfrac{9.656}{1} \times \dfrac{32.149}{ 22.345}[/tex]
Mass of Sulphur = 6.9550 mg
The Mass of oxygen can now be = mass of (Sample - Carbon - Hydrogen - Sulphur)
= (32.149 - 15.6178 - 2.6257 - 6.9550)g
= 6.9505 g
Recall that:
number of moles = mass/molar mass
Thus:
The moles of C : H : S : O are:
[tex]= \dfrac{15.6178}{12} : \dfrac{2.6257}{1.008} : \dfrac{6.9550}{32.07} : \dfrac{6.9505}{16}[/tex]
= 1 : 2 : 0.2 : 0.4
Divide by the smallest; we have:
= 1/0.2 : 2/0.2 : 0.2/0.2 : 0.4/0.2
= 5 : 10 : 1 : 2
Thus, the empirical formula is = C₅H₁₀SO₂