Answer :
Answer:
Explanation:
From the given information;
the molecular molarity of the acid and base are as follows:
For acid : 5 mL × 0.20 M = 0.1 mmol
For base: 5 mL × 0.20 M = 0.1 mmol
However;
0.05 m × 1.0 M = 0.05 mmol of acid HCl
Similarly, When the acid undergoes reaction with the base; the amount of acid and base left are as follows:
Amount of acid left:
0.1 + 0.05 = 0.15 mmol
Amount of base left:
0.1 - 0.05 = 0.05 mmol
The formula for calculating the Buffer pH is:
[tex]pH = pka + log(\dfrac{Base}{Acid} )[/tex]
Recall that for Acetic, the acid dissociation constant = 4.74
Then:
[tex]pH =4.74+ log(\dfrac{0.05}{0.15} )[/tex]
[tex]pH =4.74+ log(0.333)[/tex]
pH = 4.74 - 0.4775
pH = 4.26
Therefore, the decrease in pH is about 0.48 units