HELPP! The perimeter of a rectangle is 104 inches. The width is 6 inches less than 3 times the length. Find the
width of the rectangle.Show each step and explain what was performed for each step.

HELPP! The perimeter of a rectangle is 104 inches. The width is 6 inches less than 3 times the length. Find the width of the rectangle.Show each step and explai class=

Answer :

Answer:

Length of the rectangle = 14.5 inches

Width of the rectangle = 37.5 inches

Step-by-step explanation:

Let the length of a rectangle = a inches

Since, width of the rectangle is 6 inches less than 3 times the length,

w = 3a - 6

Perimeter of the rectangle = 104 inches

Formula to calculate the perimeter of a rectangle = 2(length + width)

104 = 2[a + (3a - 6)]

2a + 2(3a - 6) = 104 → [Starting equation]

8a - 12 = 104 → [Distributive property]

8a - 12 + 12 = 104 + 12 → [Addition property of equality]

a = [tex]\frac{116}{8}=14.5[/tex] → [Division property of equality]

a). width of the rectangle = (3a - 6) = 37.5 inches

b). length of the rectangle = 14.5 inches

The width of the rectangle is 37.5 inches and the length of the rectangle is 14.5 inches.

The perimeter of a rectangle is represented as follows:

perimeter = 2l + 2w

where

w = width

l = length

Therefore,

perimeter = 104 inches

let

the length = a

Therefore,

width = 3a - 6

Therefore,

104 = 2a + 2(3a - 6)

104 = 2a + 6a - 12

116  = 8a

a = 116 / 8

a = 14.5  inches

width = 3(14.5 ) - 6 = 37.5  inches

Therefore, the width of the rectangle is 37.5 inches and the length of the rectangle is 14.5 inches.

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