1. The half-life of polonium-210 is 138.4 days. How many milligrams of polonium-210
remain after 415.2 days if you start with 2.0 mg of the isotope?

Answer :

Okay so if the half like is 138.4 days, the mass of polonium will half every 138.4 days.

We need to work out how many half lives are in 415.2 days so we do 415.2/ 138.4 to get 3

This means the mass will half 3 times so you do

2.0/2/2/2
Or 2.0/2^3
Which gives 0.25

So 0.25mg will remain after 415.2 days


Hope this helps, let me know if you have any questions

The amount of Polonium remaining after 415.2 days has been 0.25 mg.

The half-life of a substance can be defined as the time required for the substance to be reduced to half of the initial concentration.

Half-life can be given by:

Quantity of substance remaining = Initial quantity [tex]\rm \times\;\dfrac{1}{2}^\dfrac{time}{Half\;life}[/tex]

Given, initial quantity = 2 mg

Half-life = 138.4 days

Time = 415.2 days

Quantity of substance remaining = 2 [tex]\rm \times\;\dfrac{1}{2}^\dfrac{415.2}{138.4}[/tex]

Quantity of substance remaining = 2 [tex]\times[/tex] [tex]\rm \dfrac{1}{2}^3[/tex]

Quantity of substance remaining = 2 [tex]\times[/tex] 0.125

Quantity of substance remaining = 0.25 mg

The amount of Polonium remaining after 415.2 days has been 0.25 mg.

For more information about the half-life, refer to the link:

https://brainly.com/question/24710827

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