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An object starts from rest with a constant acceleration of 8 m/s along a straight line what is the average velocity over five seconds

Answer :

elcharly64

Answer:

[tex]\bar{v}=20\ m/s[/tex]

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity changes by an equal amount in every equal period of time.

If vo is the initial speed, vf the final speed, and t the time, the acceleration is calculated as follows:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The final speed is calculated by solving the above equation:

[tex]v_f=v_o+at[/tex]

The object starts from rest (v0=0) with a constant acceleration of a= 8 m/s^2 during t=5 seconds. Thus the final speed is:

[tex]v_f=0+8 m/s^2\cdot 5\ s[/tex]

[tex]v_f=40\ m/s[/tex]

The average velocity (speed in this case) is

[tex]\displaystyle \bar{v}=\frac{v_o+v_f}{2}[/tex]

[tex]\displaystyle \bar{v}=\frac{0+40}{2}[/tex]

[tex]\boxed{\bar{v}=20\ m/s}[/tex]

Note: The average speed could also be calculated as the distance traveled x by the time. It would lead to identical results.

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