Answer:
they want a fomula that is in respect to 'b" sooo..
Step-by-step explanation:
just do the algebra.... like so..
a/b=c
move 'b" across = sign by multiplying by 1/b like soo.
(1/b)*(a/b)= (1/b)*c
a=c/b
then move the 'c' to the other side of the = sign by multiplying by 1/c
(1/c)*a = (1/c)*(c/b)
a/c = b
makes sense , also.. as a way to speed that up.. just remember you can just swap the 'b' and 'c' in that first equation
b = a/c
