Answer :
Answer:
[tex]a=-2.45\ m/s^2[/tex]
Explanation:
An object is traveling at constant acceleration if its changes in speed are constant at the same intervals of time.
The acceleration can be calculated as follows:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
Where vo is the initial speed, vf the final speed and t is the time.
The acceleration and the distance x are related through the following equation:
[tex]v_f^2=v_o^2+2.a.x[/tex]
The car has an initial speed of vo=7 m/s when the driver stops the car (vf=0) after traveling x=10 m.
The acceleration can be calculated by solving the last equation for a:
[tex]\displaystyle a=\frac{v_f^2-v_o^2}{2x}[/tex]
[tex]\displaystyle a=\frac{0-7^2}{2*10}[/tex]
[tex]\displaystyle a=\frac{-49}{20}[/tex]
[tex]\boxed{a=-2.45\ m/s^2}[/tex]