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What is the equation of a line that passes through (-6, 2) and has a slope of `-(1)/(2)'?
OA.
'y = (x)/(2)-2
'y=-(x)/(2)-1
OB.
O c.
'y = 2x +11
OD.
‘y = -2x-1

Answer :

quasarJose

Answer:

y =[tex]-\frac{1}{2}[/tex] x + 5

Step-by-step explanation:

Given parameters:

Coordinates = (-6,2)

Slope  = [tex]-\frac{1}{2}[/tex]

Unknown:

Equation of the line that passes through = ?

Solution:

The equation of a line is expressed as;

        y  =mx + c

y and x are the coordinates

m is the slope

c is the y-intercept

    let us find c;

       2  =  [tex]-\frac{1}{2}[/tex]  x 6 + c

       2  = -3 + c

        c  = 5;

The equation of the line is;

        y =[tex]-\frac{1}{2}[/tex] x + 5

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