Answer :

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[tex]M_{NaOH}=23\frac{g}{mol}+16\frac{g}{mol}+1\frac{g}{mol}=40\frac{g}{mol}\\\\ M_{Cr(C_{2}H_{3}O_{2})3}=52\frac{g}{mol}+3*(2*12\frac{g}{mol}+3*1\frac{g}{mol}+2*16\frac{g}{mol})=\\\\=229\frac{g}{mol}[/tex]

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