Step-by-step explanation: x = 73°
Draw PQ through E and parallel to AB, CD
Have x = ∠QED + ∠QEB
because PQ // CD => ∠QED = 50°
AB // PQ => ∠QEB + 157° = 180°
=> ∠QEB = 180 - 157 = 23°
=> x = 23° + 50° = 73°
( PQ is in the same direction as AB and CD )
angle efd = 130
180-50=130
angle ahe =23
180-157= 23
draw a imaginary line from h to f
this will create a triangle
now angle hfc = 90
90-50=40
now angle hfe =
90 - 23 = 67
therefore ,
x =
67+40+x=180
107 + x = 180
x = 180-107
x=73
