Answer :
Answer:
Options (3), (4) and (6)
Step-by-step explanation:
Coordinates of the vertices of the given rectangle are,
A(1, 5), B(3, 2), C(-3, -2) and D(-5, 1)
When rectangle ABCD is dilated by a scale factor of 2 about the origin,
Rule to be followed for the dilation,
(x, y) → (2x, 2y)
Therefore, image of the rectangle ABCD will be,
A(1, 5) → A'(2, 10)
B(3, 2) → B'(6, 4)
C(-3, -2) → C'(-6, -4)
D(-5, 1) → D'(-10, 2)
- Hence point B' is located at (6, 4).
- Rectangle ABCD and A'B'C'D' are similar as all the angles of image will be same as the pre-image after rigid transformation (dilation).
- Let the equation of the line B'C' is,
y = mx + b
Slope (m) = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{4-2}{6-3}[/tex]
= [tex]\frac{2}{3}[/tex]
Since B'C' will pass through origin, y-intercept will be zero.
Therefore, equation of B'C' will be,
y = [tex]\frac{2}{3}x[/tex]
Options (3), (4) and (6) are the correct options.
Answer:
well im confused but dont you have to find the prime too
Step-by-step explanation: