Answer :

Answer:

A

Step-by-step explanation:

Given

f(x) = x + [tex]\frac{\sqrt{x+1} }{x-1}[/tex]

To evaluate f(3), substitute x = 3 into f(x) , that is

f(3) = 3 + [tex]\frac{\sqrt{3+1} }{3-1}[/tex]

     = 3 + [tex]\frac{\sqrt{4} }{2}[/tex]

     = 3 + [tex]\frac{2}{2}[/tex]

     = 3 + 1

     = 4 → A

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