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I NEED AN ANSWER ASAP A surveyor finds the angle of elevation to the top of a building to be 75°. He is 20 meters from the base of the building. How tall is the building?​

I NEED AN ANSWER ASAP A surveyor finds the angle of elevation to the top of a building to be 75°. He is 20 meters from the base of the building. How tall is the class=

Answer :

Answer: 74.6

we draw a right triangle ABC, have: ∠ABC = 90°,  AB = 20 and ∠BAC = 75°, the height of the building is BC

we also have: tan 75° = BC/AB = BC/20

=> BC = tan 75°. 20 = 40 + 20√3 ≈ 74.6

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