Answer:
Q = 5350.2 Joules.
Explanation:
Given the following data;
Mass, m = 26. 5g
Initial temperature, T1 = 0°C
Final temperature, T2 = 48.3°C
Specific heat capacity of water, c = 4.18 J/g°C.
*To find the quantity of heat*
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
- Q represents the heat capacity or quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity of water.
- dt represents the change in temperature.
dt = T2 - T1
dt = 48.3 - 0
dt = 48.3°C
Substituting the values into the equation, we have;
[tex] Q = 26.5*4.18*48.3[/tex]
Q = 5350.2 Joules.
Therefore, the amount of heat absorbed is 5350.2 Joules.
