A chemist prepares a solution by adding 253 mg of Co(NO3)2 (MW = 182.94 g/mol ) to a volumetric flask, and then adding water until the total volume of the contents of the flask reaches the calibration line that indicates 100 mL . Determine the molarity of the prepared solution.

Answer :

ardni313

The molarity of the prepared solution : 0.014 M

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\tt \large {\boxed {\bold {M ~ = ~ \dfrac {n} {V}}}[/tex]

Where

M = Molarity

n = number of moles of solute

V = Volume of solution

mass of solute (Co(NO₃)₂) :253 mg = 0.253 g

moles of solute (Co(NO₃)₂) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{0.253~g}{182.94}\\\\mol=0.0014[/tex]

Volume of solution = 100 ml=0.1 L

The molarity :

[tex]\tt molarity(M)=\dfrac{0.0014}{0.1}=0.014[/tex]