Answer :
We know that:
v² = v₀² - 2ah
Where v is the final velocity whos value at the maximum height is zero.
v₀ is the initial velocity
h is the maximum height
a = g = 10 m/s² the acceleration due gravity on Earth
Solving for v0:
[tex]v_0=\sqrt{v^2+2ah} \\\\v_0 =\sqrt{ 0+2(10\;m/s^2)(50000\;m)}\\\\v_0 =\sqrt{ 2(10\;m/s^2)(50000\;m)} \\\\v_0 = 1000\;m/s[/tex]
Answer:
1000 m/s ( 990.45 m/s to be exact)
Explanation:
If we use one of the SUVAT equations, i.e.,
2as = (v^2) - (u^2) where;
s = distance, a = acceleration, v = final velocity, u = initial velocity
At max point the rocks are considered stationery, which makes v = 0, the height is 50,000m which makes s = 50,000, the acceleration is -9.81, as the object decelrates to 0
2(-9.81)(50000) = (0)^2 - (u)^2
-981000 = - u^2
u = sqr root( 981000)
u = 990.45 m/s = 1000 m/s