Answer :
Answer:
3
Step-by-step explanation:
It's given that ΔDEF ∼ΔXYZ . So the corresponding sides of both triangles will be proportional to each other.
[tex] = > \frac{de}{xy} = \frac{ef}{yz} = \frac{df}{xz} [/tex]
DE = 4 ; XY = 4(n + 1) ; EF = 5 ; YZ = 7n - 1
Putting all these values gives ,
[tex] \frac{4}{4(n + 1)} = \frac{5}{7n - 1} [/tex]
[tex] = > \frac{1}{n + 1} = \frac{5}{7n - 1} [/tex]
[tex] = > 7n - 1 = 5(n + 1)[/tex]
[tex] = > 7n - 1 = 5n + 5[/tex]
[tex] = > 7n - 5n = 5 + 1[/tex]
[tex] = > 2n = 6[/tex]
[tex] = > n = \frac{6}{2} = 3[/tex]
Answer:
answer is 3
Step-by-step explanation:
they are correct