What is the range of y = sin-1x?

A.) [–1, 1]
B.) [0, π]
C.) Left-bracket negative StartFraction pi Over 2 EndFraction, StartFraction pi Over 2 EndFraction right-bracket
D.) (–∞, ∞)

Answer :

Answer:

c

Step-by-step explanation:

This question is based on the trigonometry. Therefore, the correct option is C,  i,e.  [tex][\dfrac{-\pi}{2} ,\dfrac{\pi}{2}][/tex] is the range of [tex]Sin^{-1} x[/tex].

Given:

Function is y = [tex]Sin^{-1} x[/tex].

We need to determined the range of the function  y = [tex]Sin^{-1} x[/tex].

As we know that,

Domain of [tex]Sin^{-1} x[/tex] is −1 ≤ [tex]Sin^{-1} x[/tex] ≤ 1.

By using the graph of y = [tex]Sin^{-1} x[/tex] . we would be find the range.

We observe in graph that,

The upper limit of graph of given function is [tex]+\dfrac{\pi}{2}[/tex].

And, the lower limit of graph of given function is [tex]-\dfrac{\pi}{2}[/tex].

Thus, the range of  y = [tex]Sin^{-1} x[/tex] function is [tex][\dfrac{-\pi}{2} ,\dfrac{\pi}{2}][/tex].

Therefore, the correct option is C,  i,e.  [tex][\dfrac{-\pi}{2} ,\dfrac{\pi}{2}][/tex] is the range of [tex]Sin^{-1} x[/tex].

For more details, prefer this link:

https://brainly.com/question/15274395

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