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Consider the proof.
Given: Segment AB is parallel to line DE.
Prove:StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction



What is the missing statement in Step 5?
AC = BC
AC/DC = BC/EC
AD = BE
AD/DC = BE/EC

Consider the proof. Given: Segment AB is parallel to line DE. Prove:StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction What is the class=
Consider the proof. Given: Segment AB is parallel to line DE. Prove:StartFraction A D Over D C EndFraction = StartFraction B E Over E C EndFraction What is the class=

Answer :

Answer:

B

Step-by-step explanation:

did it on edge

The missing statement in step 5 is AC/DC = BC/EC by the property of similarity law for triangles option second is correct.

What is the similarity law for triangles?

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

We have:

Segment AB is parallel to line DE.

AD/DC = BE/EC

As we know similarity law for triangles states that the ratio of the corresponding sides is in the same proportions.

By using the similarity law for triangles:

AC/DC = BC/EC

Thus, the missing statement in step 5 is AC/DC = BC/EC by the property of similarity law for triangles option second is correct.

Learn more about the similarity of triangles here:

brainly.com/question/8045819

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