$9500 is invested, part of it at 12%, and part of it at 9%, For a certain year, the total yield is $1032.00. How much was invested at each rate?. How much was invested at 12%. How much was invested at 9%.
Let us assume the amount invested at 12% = x Let us assume the amount invested at 9% = y Total amount invested = $9500 Total yield = $1032 Then x + y = 9500 x = 9500 - y and 0.12x + 0.09y = 1032 Putting the value of "x" in the second equation, we get 0.12(9500 - y) + 0.09y = 1032 1140 - 0.12y + 0.09y = 1032 0.03y = 108 y = 3600 Putting the value of y in the first equation, we get x = 9500 - 3600 = 5900 I hope the procedure is clear enough for you to understand.
