Answered

If a DNA strand has 32 % guanine before semi conservative replication occurs, what
percent thymine will each new strand have after replication?

Answer :

Answer:I believe that the answer would be 18

Explanation:

32 divided by 2 is 18

luisvaschetto

If a DNA strand has 32% Guanine before semi-conservative replication occurs, then the percent Thymine will each new strand have after replication will be 18%.

  • The deoxyribonucleic acid (DNA) is a double helix molecule composed of four types of nucleotides: Adenine (A), Thymine (T), Cytosine (C) and Guanine (G).

  • In DNA, Adenine (A) always pairs with Thymine (T), whereas Cytosine (C) always pairs with Guanine (G).

  • The replication of DNA is semi-conservative because after replication each DNA molecule contains one original DNA strand and one newly-synthesized DNA strand.

  • If a DNA molecule contains 32% of Guanine, then the content of G + C is equal to 64%, so the content of T + A is equal to 36% (64 + 36 = 100) and T content is 18% (18 + 18 = 36).

In conclusion, if a DNA strand has 32% of Guanine before replication, then the percent of Thymine after replication will be 18%.

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