Answer :
Answer:
The correct output will be "46.76 h.p.".
Explanation:
The given values are:
Gasoline's energy content,
= 46000 J/g
= 4.6 x10⁷ J/kg
Fuel usage,
= 13 kg/h
= [tex]\frac{13}{3600} \ kg/s[/tex]
Fuel efficiency,
= 21%
= 0.21
Now,
The average output will be:
= [tex](Energy \ content \ of \ gasoline)\times (fuel \ usage)\times (fuel \ efficiency)[/tex]
On substituting the values, we get
= [tex]4.6\times 10^7\times (\frac{13}{3600} )\times 0.21\times (\frac{1}{746}) h.p.[/tex]
= [tex]46.76 \ h.p.[/tex]
Answer:
the average horsepower output of the engine is 46.76 hp
Explanation:
The computation of the average horsepower output of the engine is shown below
The output of the engine is
= (Energy content of gasoline) × (usage of the fuel ) × (Fuel efficiency)
As we know that
1 hp = 746 W
where,
Energy content of gasoline = 46000 J / g = 4.6 × 107 J/kg
Usage of the fuel = 13 kg / h = 13 ÷ 3600 kg/s
Fuel efficiency = 21% = 0.21
Therefore, the output of the engine is
= 4.6 × 107 × (13 ÷ 3600) × 0.21 × (1 ÷ 746) h.p.
= 46.76 h.p.
hence, the average horsepower output of the engine is 46.76 hp