Answer :

calculista

we have

[tex]2x+3y=-12[/tex]

Isolate variable y

[tex]2x+3y=-12[/tex]

Subtract [tex]2x[/tex] both sides

[tex]3y=-2x-12[/tex]

Divide by [tex]3[/tex] both sides

[tex]y=-\frac{2}{3}x-4[/tex]

the slope m is equal to

[tex]m=-\frac{2}{3}[/tex]

therefore

the answer is the option B

[tex]-\frac{2}{3}[/tex]

The slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is [tex]\frac{-2}{3}[/tex].

Given that,

2x + 3y = -12

Now here we isolated the variable y

2x + 3y = -12

Now subtract 2x from both sides

3y = -2x - 12

Now divide by 3 in both the sides.

[tex]y = \frac{-2}{3}x - 4[/tex]

Now

The slope m should be [tex]\frac{-2}{3}[/tex].

Therefore we can conclude that the slope of the line is represented by the equation 2x+3y= -12 and 2x+3y= -12 is [tex]\frac{-2}{3}[/tex].

Learn more: brainly.com/question/3605446

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