Answer :
The equation
x = log(base b) of y
is equivalent to
y = b^x
So if y = 1, we have
1 = b^x
which implies that x = 0 since b is not 0.
x = log(base b) of y
is equivalent to
y = b^x
So if y = 1, we have
1 = b^x
which implies that x = 0 since b is not 0.