Answer :
slope of tangent line = dy/dx = 2x + 3
2x + 3 = -1
x = -2
y = -2^2 + 3 (-2) + 1 = -1
Tangent line passed through point (-2 , 1)
k = x + y
k = -2 - 1
k = -3
hope this helps
2x + 3 = -1
x = -2
y = -2^2 + 3 (-2) + 1 = -1
Tangent line passed through point (-2 , 1)
k = x + y
k = -2 - 1
k = -3
hope this helps