Answer :
Answer:
[tex]PtCl_4[/tex]
Explanation:
Hello!
In this case, since HCl and Pt react according to the following chemical equation:
[tex]HCl+Pt\rightarrow PtCl_x+H_2[/tex]
Whereas PtClx is the compound containing Pt and Cl; thus, since 1.018 g out of 1.778 g correspond to Pt and therefore 0.760 g to chlorine, so we determine the empirical formula of this compound by firstly computing the moles of each element:
[tex]n_{Pt}=1.018gPt*\frac{1molPt}{195.084gPt}=0.00522molPt\\\\\\n_{Cl}=0.760gCl*\frac{1molCl}{35.45gCl} =0.0214molCl[/tex]
Now, we divide the each moles by those of Pt as the fewest ones in order to compute their subscripts in the empirical formula:
[tex]Pt=\frac{0.00522}{0.00522}=1 \\\\Cl=\frac{0.0214}{0.00522} =4[/tex]
Thus, the required formula is:
[tex]PtCl_4[/tex]
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