Answer :

Nirina7
it is easy after using formula of the complex numbers
z1= 5(cos25Deg + i sin25Deg)
z2= 2(cos80Deg + isin80Deg)
so z1/z2 =5/2cis(25Deg-80Deg)=5/2cis(-55Deg)
but we know that sin(-55Deg)= - sin(55Deg), and cos(-55Deg)=cos(55Deg),
finally the answer is Z=5/2(cos55Deg-i sin55Deg) (Z=z1/z2)
turanganik

5/2(cos305 degrees + i sin305 degrees)

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