we know that
[tex]4.1m= \frac{41}{10}m[/tex]
Part a) how many strip 7/10m long can he cut?
divide [tex] \frac{41}{10} [/tex] by [tex] \frac{7}{10} [/tex]
so
[tex] \frac{ \frac{41}{10}}{ \frac{7}{10}} = \frac{41}{7} \\ \\ =5.85 \\ \\ =5strip[/tex]
the answer part a) is
[tex]5strip[/tex]
Part b) how much wire will he have left over
[tex]5* \frac{7}{10} =3.5m[/tex]
[tex]3.5[/tex]m of wire wil be used in cutting possible [tex] \frac{7}{10} [/tex]m pieces
so
wire left over will be
[tex]4.1-3.5=0.6 m[/tex]
the answer Part b) is
[tex]0.6m[/tex]
