Answer :

The atoms of helium are required to equalize the mass of a silver atom is 8.4 x 10 ⁻⁴⁸.

What are atoms?

Atoms are the minute particles that are present inside elements.

Atomic mass of silver is 107.86 g/mol

Mass of one atom of silver will be

[tex]\dfrac{ 107.86 }{6.022 \times 10^{-23}} = 1.79 \times 10^2^4[/tex]

Atomic mass of helium is 6.941

[tex]\dfrac{6.022 \times 10^{-23}}{4.0 \times 1.79 \times 10^2^4 } = 8.4 \times 10^{-48}[/tex]

Thus, the atoms of helium are required to equalize the mass of a silver atom is 8.4 x 10 ⁻⁴⁸.

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