Answer:
1. diameter=8 kilometres
2. area=98.96 inches
3. 37m
Step-by-step explanation:
1. diameter= 2*radius
2. area of sector=θ out of 360*π[tex]r^{2}[/tex] where θ is the angle
3. area of garden=π[tex]r^{2}[/tex]
706.5=π[tex]r^{2}[/tex]
[tex]r^{2}[/tex]=706.5/π
= 225(nearest whole)
r=[tex]\sqrt{225}[/tex]=15m
we now use Pythagoras theorem to find length of each pathway
[tex]40^{2} =15^{2} +x^{2}[/tex]
1600=225+[tex]x^{2}[/tex]
[tex]x^{2}[/tex]=1600-225=1375
x=[tex]\sqrt{1375}[/tex]=37 m (to nearest whole)
The tangent pathways from the entrance form right triangles from which
the length of the pathway which are the sides of the triangle, can be found.
Reasons:
1. The radius of the particle accelerator = 4 kilometers
The diameter of the particle accelerator = 2 × The radius
Therefore;
The diameter = 2 × 4 km = 8 km
The accelerator's diameter is 8 kilometers
2. The area of a sector of a circle is A = [tex]\displaystyle \frac{\theta}{360^{\circ}} \times \pi \cdot r^2[/tex]
The angle subtended by the sector, θ = 140°
The radius of the sector, r = 9 inches
Therefore;
[tex]\displaystyle A = \frac{140^{\circ}}{360^{\circ}} \times \pi \times 9^2 = \mathbf{ 31.5 \cdot \pi}[/tex]
The area of the shaded sector, A = 31.5·π in.² ≈ 98.96 in.²
3. The distance from the center to the main entrance, d = 40 m
Area of the circular garden, A = 706.5 m²
Solution:
The radius of the garden, r = √(A ÷ (π))
Therefore;
r = √(706.5 ÷ (π)) ≈ 15
The tangent pathways are perpendicular to the radius of the circular garden.
Therefore, the pathway from the entrance, the 40 m. distance from the center to the entrance and the radius form a right triangle.
Where;
The 40 m. distance = The hypotenuse side
By Pythagorean theorem, we have;
40² = r² + (Length of the pathway)²
Which gives;
40² = 15² + (Length of the pathway)²
Length of the pathway ≈ √(40² - 15²) ≈ 37.1
The length of each pathway is approximately 37.1 m.
Learn more about Pythagorean theorem here:
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