Answer :
The equation of the line passing through [tex] (x_1,y_1) [/tex] and [tex] (x_2,y_2) [/tex] is
[tex] \frac{x-x_1}{y-y_1} =\frac{x_2-x_1}{y_2-y_1} [/tex]. Here
[tex] \frac{y_2-y_1}{x_2-x_1} [/tex] is the slope of the line.
Substituting numerical values, the equation of the line is
[tex] \frac{x-0}{y-5} =\frac{-2-0}{11-5} \\
\frac{x}{y-5} =-\frac{1}{3} \\
3x=5-y\\
3x+y=5 [/tex]
The equation of the line is [tex] 3x+y=5 [/tex]