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A balloon is filled with helium at sea level. The volume was measured to be 3.1 liters at a pressure of 0.97 atm. If the balloon is released, it drifts upward. At a height of 4 kilometers, the pressure is measured to be 0.61 atm. What is the new volume of the balloon?

Answer :

I'm pretty sure the answer is 4.9L
transitionstate

Answer:

                 4.93 L

Solution:

              According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportinal to the applied Pressure". Mathmatically the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂    ----------- (1)

Data Given;

                  P₁  =  0.97 atm

                  V₁  =  3.1 L

                  P₂  =  0.61 atm

                  V₂  =  ?

Solving equation 1 for V₂,

                   V₂  =  P₁ V₁ / P₂

Putting values,

                   V₂  =  (0.97 atm × 3.1 L) ÷ 0.61 atm

                   V₂  =  4.93 L

Result:

            As the pressure has decreased from 0.97 atm to 0.61 atm, therefore, volume got increased from 3.1 L to 4.93 L.

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