In Δ ABC the value of cos B is [tex]\frac{12}{13}[/tex] .
What is the trigonometric ratio?
Trigonometric ratios can be calculated by taking the ratio of any two sides of the right-angled triangle.
The basic Trigonometric ratios are :
- sin θ = [tex]\frac{Perpendicular}{Hypotenuse}[/tex]
- cos θ = [tex]\frac{Base}{Hypotenuse}[/tex]
- tan θ = [tex]\frac{Perpendicular}{Base}[/tex]
- sec θ = [tex]\frac{Hypotenuse}{Base}[/tex]
- cosec θ = [tex]\frac{Hypotenuse}{Perpendicular}[/tex]
- cot θ = [tex]\frac{Base}{Perpendicular}[/tex]
According to the question
In Δ ABC ,
Perpendicular for ∠B = 5
Base for ∠B = 12
Hypotenuse for ∠B = 13
Cos B = [tex]\frac{Base}{Hypotenuse}[/tex]
Cos B = [tex]\frac{12}{13}[/tex]
Hence, In Δ ABC the value of cos B is [tex]\frac{12}{13}[/tex] .
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