Answer :
Answer:
The wavelength of the light in a vacuum is 575.89 nm
Explanation:
The given parameter in the are;
The wavelength of the ray of light in water, λ₁ = 433 nm
The refractive index of water, n₁ = 1.33
The relationship between wavelength, λ, and refractive index, 'n', is presented as follows;
λ₁·n₁ = λ₂·n₂
Where;
λ₁ and λ₂ are the wavelength of the wave within the two mediums
n₁ and n₂ are the respective refractive indices of the mediums
The refractive index of vacuum, n₂ = 1
Let λ₂ represent the wavelength of light in vacuum
Therefore, we have;
1.33 × 433 nm = 1 × λ₂
∴ λ₂ = 1.33 × 433 nm/1 = 575.89 nm
Therefore, the wavelength in a vacuum, λ₂ = 575.89 nm