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A stationary 2 kg football is kicked by a footballer, the football moves off with a velocity of 5 m/s. If the footballer is in contact with the football for 0.5 s, what is the average force applied by the footballer
on the football?
Please helppp!!!!

Answer :

Answer:

F = 20 N

Explanation:

Given that,

Mass of the football, m = 2 kg

Initial speed, u = 0

Final speed,v = 5 m/s

The time of contact, t = 0.5 s

We need to found the average force applied by the footballer  on the football. We can find it using the formula.

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{2\times (5-0)}{0.5}\\\\F=20\ N[/tex]

So, the required force is 20 N.

Answer:

F=20

Explanation:

f=20

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