Answer :
Answer: [tex]2C_{12}H_{26}(l)+37O_2(g)\rightarrow 24CO_2(g)+26H_2O(g)[/tex]
2. 369 L
Explanation:
1. Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.
The balanced chemical reaction is:
[tex]2C_{12}H_{26}(l)+37O_2(g)\rightarrow 24CO_2(g)+26H_2O(g)[/tex]
2. To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{220g}{170.3g/mol}=1.29moles[/tex]
According to stoichiometry :
2 mole of dodecane produces = 24 moles of carbon dioxide
Thus 1.29 moles of dodecane produces = [tex]\frac{24}{2}\times 1.29=15.5 moles[/tex] of carbon dioxide
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1 atm
V = Volume of gas = ?
n = number of moles = 15.5
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]17^0C=(17+273)K=290K[/tex]
[tex]V=\frac{nRT}{P}[/tex]
[tex]V=\frac{15.5\times 0.0821L atm/K mol\times 290K}{1atm}=369L[/tex]
Thus the volume of carbon dioxide gas that is produced is 369 L