Answer:
282,250 joules
Explanation:
Given that :
Mass of liquid water = 125 gram.
Latent heat of vaporization, L = 2258 J/g
Recall :
Q = mL
Where, Q = quantity of heat required in Joules
Mass) m
L = latent heat of vaporization
Q = mL
Q = 125 g * 2258j/g
Q = 282,250 joules
