Answer:
a = 1.055 x 10¹⁷ m/s²
Explanation:
First, we will find the force on electron:
[tex]E = \frac{F}{q}\\\\F = Eq\\[/tex]
where,
F = Force = ?
E = Electric Field = 6 x 10⁵ N/C
q = charge on electron = 1.6 x 10⁻¹⁹ C
Therefore,
[tex]F = (6\ x\ 10^5\ N/C)(1.6\ x\ 10^{-19}\ C)\\[/tex]
F = 9.6 x 10⁻¹⁴ N
Now, we will calculate the acceleration using Newton's Second Law:
[tex]F = ma\\a = \frac{F}{m}\\[/tex]
where,
a = acceleration = ?
m = mass of electron = 9.1 x 10⁻³¹ kg
therefore,
[tex]a = \frac{9.6\ x\ 10^{-14}\ N}{9.1\ x\ 10^{-31}\ kg}\\\\[/tex]
a = 1.055 x 10¹⁷ m/s²
