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A chemistry student experiments on producing table salt by reacting pure sodium cubes with confined chlorine gas. If the procedure is successful, how much salt is produced with 160 g of chlorine gas used? *
with solution pls

Answer :

Answer: 263 grams of salt is produced.

Explanation:

To calculate the moles :

[tex]\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}[/tex]    

[tex]\text{Moles of} Cl_2=\frac{160g}{71g/mol}=2.25moles[/tex]

The balanced chemical reaction is:

[tex]2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)[/tex]  

According to stoichiometry :

1 mole of [tex]Cl_2[/tex] produce = 2 moles of [tex]NaCl[/tex]

Thus 2.25 moles of [tex]Cl_2[/tex] will produce =[tex]\frac{2}{1}\times 2.25=4.50moles[/tex]  of [tex]NaCl[/tex]

Mass of [tex]NaCl=moles\times {\text {Molar mass}}=4.50moles\times 58.5g/mol=263g[/tex]

Thus 263 grams of salt is produced.

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