A cedar chest is a shaped like a rectangular prism. The cedar chest is 2 feet tall, 4 feet wide, and 2 feet deep What is the surface area of the cedar chest? Enter your answer in the box​

Answer :

Answer:

40 ft^2

Step-by-step explanation:

lateral surface area -Slat = 24 ft^2

top surface area-Stop = 8 ft^2

bottom surface area-Sbot = ft m^2

24+8+8= 40

total surface area-Stot = 40 ft^2

The surface area of a rectangular prism or cedar chest of 2 feet tall, 4 feet wide, and 2 feet deep is 40ft sq.

The length of a rectangular prism is 2 feet.

The width of a rectangular prism is 4 feet.

The height of a rectangular prism is 2 feet.

we need to find the surface area of a rectangular prism.

What is a rectangular prism?

A rectangular prism is a 3-dimensional representation, that has six rectangular faces two at the top and bottom and four are lateral faces. A rectangular prism is also known as a cuboid.

The surface area of a rectangular prism = 2(lb + bh + lh)

So, the surface area of a rectangular prism = 2(lb + bh + lh)

[tex]=2(2\times4+4\times2+2\times2)\\=2(8+8+4)\\=40[/tex]

Hence, the surface area of a rectangular prism or cedar chest is 40ft sq.

Learn more about a rectangular prism here:

https://brainly.com/question/21308574

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