Answer :
the answer is
2cosx + √3 = 0 so cosx = -√3/2
2sinx-1= 0, , so sinx = ½
The solution is
X= arcos (-√3/2), or x= arc sin(1/2)
X=5pi/6 + 2kpi or
X= pi/6 +2kpi
2cosx + √3 = 0 so cosx = -√3/2
2sinx-1= 0, , so sinx = ½
The solution is
X= arcos (-√3/2), or x= arc sin(1/2)
X=5pi/6 + 2kpi or
X= pi/6 +2kpi