Answer :

samuelpoly011

Answer:

cos x is the answer.

Step-by-step explanation:

secx - tanx sinx

[tex]\frac{1}{cosx} - \frac{sinx}{cosx} * sinx\\\\\frac{1}{cosx} - \frac{sin^{2}x}{cosx}\\\\\frac{1-sin^{2}x}{cosx} \\\\\frac{cos^{2}x }{cosx} \\\\cosx[/tex]

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