Answer :

Answer:

84 ounces of pure gold

Step-by-step explanation:

Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy that is 75% gold?

Pure gold = 100% gold

Let the number of ounces of pure gold = x

Hence, we have the equation

40% × 60 ounces + 100%× x ounces = 75%(60 + x)ounces

= 0.4 × 60 + 1x = 0.75(60 + x)

= 24 + x = 45 + 0.75x

Collect like terms

x - 0.75x = 45 - 24

0.25x = 21

x = 21/0.25

x = 84 ounces

Therefore, we need 84 ounces of pure gold

Ritmeks

84 ounces of pure gold must be added

The first is to write out the parameters

Jess has 60 ounces of alloy

40% of this alloy is pure gold

The number of ounces that should be added can be calculated as follows;

Let y represent the unknown

40/100(y)(60) + 100/100(y)= 75/100(60+y)

24 + y= 0.75(60+y)

25 + y= 45 + 0.75y

24 - 45= 0.75y -y

-21= -0.25y

y= 21/0.25

y= 84

Hence the number of ounces of pure gold required is 84 ounces

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